Question

The above spring has a spring constant of 29 N/m. The μ between the box and the surface is 0.3. The box has a mass of 1 kg.

What is the maximum distance that the spring can be stretched from equilibrium before the box begins to slide back?

Answer 1

weight = m g = 1*9.81 = 9.81 N
max friction force = .3*9.81 = 2.94 N

2.94 = k x = 29 x
x = .101 meter = 10.1 cm

Answer 2

thanks

Answer 3

You are welcome :)

Answer 4

how did you get the 9.81?

Answer 5

gravity on earth g = 9.81 m/s^2

Answer 6

ok, thanks again

Answer 7

weight = mass * g = 9.81 m