Asked by Help

The above spring has a spring constant of 29 N/m. The μ between the box and the surface is 0.3. The box has a mass of 1 kg.

What is the maximum distance that the spring can be stretched from equilibrium before the box begins to slide back?
Answered by Damon
weight = m g = 1*9.81 = 9.81 N
max friction force = .3*9.81 = 2.94 N

2.94 = k x = 29 x
x = .101 meter = 10.1 cm
Answered by =)
thanks
Answered by Damon
You are welcome :)
Answered by question
how did you get the 9.81?
Answered by Damon
gravity on earth g = 9.81 m/s^2
Answered by thanks
ok, thanks again
Answered by Damon
weight = mass * g = 9.81 m
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