Asked by Help
                The above spring has a spring constant of 29 N/m. The μ between the box and the surface is 0.3. The box has a mass of 1 kg. 
What is the maximum distance that the spring can be stretched from equilibrium before the box begins to slide back?
            
        What is the maximum distance that the spring can be stretched from equilibrium before the box begins to slide back?
Answers
                    Answered by
            Damon
            
    weight = m g = 1*9.81 = 9.81 N
max friction force = .3*9.81 = 2.94 N
2.94 = k x = 29 x
x = .101 meter = 10.1 cm
    
max friction force = .3*9.81 = 2.94 N
2.94 = k x = 29 x
x = .101 meter = 10.1 cm
                    Answered by
            =)
            
    thanks
    
                    Answered by
            Damon
            
    You are welcome :)
    
                    Answered by
            question
            
    how did you get the 9.81?
    
                    Answered by
            Damon
            
    gravity on earth g = 9.81 m/s^2
    
                    Answered by
            thanks
            
    ok, thanks again
    
                    Answered by
            Damon
            
    weight = mass * g = 9.81 m
    
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