Asked by Khadija

An trunk weighing 518 N is resting on a plane inclined 25° above the horizontal.
(a) Calculate the magnitude of the acceleration of the trunk (ignore friction).

(b) After 6.00 s, how fast would the trunk be moving?

Answers

Answered by Henry
a. Fp = 518*sin25 = 218.9 N. = Force
parallel to the incline.

m*g = 518 N.
m = 518/g = 518/9.8 = 52.86 kg.

a = F/m = 218.9/52.86 = 4.14 m/s^2.

b. V = Vo + a*t = 0 + 4.14*6=24.85 m/s.

Answered by Aidan
yo this is garbage, didn't solve my question
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