Question

An trunk weighing 518 N is resting on a plane inclined 25° above the horizontal.
(a) Calculate the magnitude of the acceleration of the trunk (ignore friction).

(b) After 6.00 s, how fast would the trunk be moving?

Answer 1

a. Fp = 518*sin25 = 218.9 N. = Force
parallel to the incline.

m*g = 518 N.
m = 518/g = 518/9.8 = 52.86 kg.

a = F/m = 218.9/52.86 = 4.14 m/s^2.

b. V = Vo + a*t = 0 + 4.14*6=24.85 m/s.

Answer 2

yo this is garbage, didn't solve my question