Asked by Lisa

You push a 320 N trunk up a 20.0° inclined plane at a constant velocity by exerting a 213 N force parallel to the plane's surface.
(a) What is the component of the trunk's weight parallel to the plane?

(b) What is the sum of all forces parallel to the plane's surface?

(c) What is the magnitude and direction of the friction force?



upward, perpendicular to the plane

upward along the plane

downward, perpendicular to the plane

downward along the plane

(d) What is the coefficient of friction?
Answered by bobpursley
You need to try to grunt through this yourself. I will be happy to critique your thinking.
Answered by Anonymous
What force would you have to exert on a 326-N trunk up a 21.0° inclined plane so that it would slide down the plane with a constant velocity? What would be the direction of the force? (The coefficient of friction between the plane and the trunk is 0.329.)
Answered by Keepo
ayyy lmao
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