| 3 2 7 | x1 | | 46 |

Question

| -2 1 4 | x2 | = | 12 |
| 6 -5 8 | x3 | | 60 |

(b). Solve the system using the inverse of the coefficient matrix.
(x1, x2, x3) = (________)

Answer 1

well, since AX = B,
X = A^-1B
X = 1/6 {23,2,29}

The inverse is at

http://www.wolframalpha.com/input/?i=inverse%28{{+3%2C+2%2C+7}%2C+{+-2%2C+1%2C+4}%2C{+6%2C+-5%2C+8}}%29

and the solution is at

http://www.wolframalpha.com/input/?i=inverse%28{{+3%2C+2%2C+7}%2C+{+-2%2C+1%2C+4}%2C{+6%2C+-5%2C+8}}%29*{{46}%2C{12}%2C{60}}

Answer 2

i need the 3 numbers for the answer, how do i find that?

Answer 3

Do you know how to find the inverse of a 3by3 matrix?

I got the following:
28 -51 1
40 -18 -26
4 27 7
each is divided by 192

so multiply the above inverse matrix by
46
12
60
then divide each result by 192 for your x1, x2, x3

Answer 4

aside from the fact that I gave you the three numbers as the vector X, take a look at the 2nd url I gave you.