Asked by Melissa
Two teams of nine members each engage in a tug of war. The first team's members have average masses of 64 kg and exert average forces of 1350 N horizontally. The second team's members have average masses of 69 kg and exert average forces of 1365 N horizontally.
(a) What is the acceleration of the two teams?(in the direction the heavy team is pulling)
(b) What is the tension in the section of rope between the teams?
(a) What is the acceleration of the two teams?(in the direction the heavy team is pulling)
(b) What is the tension in the section of rope between the teams?
Answers
Answered by
Damon
net Force = 9(1365-1350)
mass = 9(64) + 9(69)
so
a = 9(1365-1350) /[9(64) + 9(69) ]
a = 15/133 = .113 m/s^2
b)
T - 9(1350) = 9(64)(.113)
T = 12,215
mass = 9(64) + 9(69)
so
a = 9(1365-1350) /[9(64) + 9(69) ]
a = 15/133 = .113 m/s^2
b)
T - 9(1350) = 9(64)(.113)
T = 12,215