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A 0.505-g sample of a compound is dissolved in enough water to form 100.0 mL of solution. This solution has an osmotic pressure of 2.56 atm at 25°C. If each molecule of the solute dissociates into two particles (in this solvent), what is the molar mass of this solute?
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Answered by
DrBob222
pi = inRT
pi = 2.56 atm
i = 2
R = 0.08206
T = 298K
Solve for n, then n = grams/molar mass
You know grams and n, solve for molar mass.
pi = 2.56 atm
i = 2
R = 0.08206
T = 298K
Solve for n, then n = grams/molar mass
You know grams and n, solve for molar mass.
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