Asked by Odunayo
A rectangular field has a perimeter of 442m. If the length and the width are in ratio 12:5 find the diagonal and 2 area of the rectangular field
Answers
Answered by
Bosnian
L / W = 12 / 5 Multiply both sides by 5
5 L / W = 12 Multiply both sides by W
5 L = 12 W Divide both sides by 5
L = ( 12 / 5 ) W
L = 2.4 W
P = 2 W + 2 L =
2 ( W + L ) = 442 Divide both sides by 2
W * L = 221
W + 2.4 W = 221
3.4 W = 221 Divide both sides by 3.4
W = 221 / 3.4
W = 65 m
L = 2.4 W
L = 2.4 * 65 = 156 m
d = sqrt ( L ^ 2 + W ^ 2 )
d = sqrt ( 156 ^ 2 + 65 ^ 2 )
d = sqrt ( 24336 + 4225 )
d = sqrt ( 28561 )
d = 169 m
A = W * L = 65 * 156 = 10,140 m ^ 2
5 L / W = 12 Multiply both sides by W
5 L = 12 W Divide both sides by 5
L = ( 12 / 5 ) W
L = 2.4 W
P = 2 W + 2 L =
2 ( W + L ) = 442 Divide both sides by 2
W * L = 221
W + 2.4 W = 221
3.4 W = 221 Divide both sides by 3.4
W = 221 / 3.4
W = 65 m
L = 2.4 W
L = 2.4 * 65 = 156 m
d = sqrt ( L ^ 2 + W ^ 2 )
d = sqrt ( 156 ^ 2 + 65 ^ 2 )
d = sqrt ( 24336 + 4225 )
d = sqrt ( 28561 )
d = 169 m
A = W * L = 65 * 156 = 10,140 m ^ 2
Answered by
Bosnian
P = 2 W + 2 L =
2 ( W + L ) = 442 Divide both sides by 2
W + L = 221
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