Asked by Anne
A rectangular field is to be enclose by 800 meters of fencing and the fourth side with be along the side of a barn.
A) What dimensions will give the maximum area?
B) What is the maximum area?
A) What dimensions will give the maximum area?
B) What is the maximum area?
Answers
Answered by
Reiny
let the single side by y
let the two other sides be x each
so 2x+y = 800
y = 800-2x
area = xy
= x(800-2x)
= -2x^2 + 800x
Since you rated this grade 10 , I will assume you don't have Calculus, so let's complete the square
area = -2(x^2 - 400x <>+40000-40000</b>)
= -2( (x-200)^2 - 40000)
= -2(x-200)^2 + 80000
the max area is 80,000 m^2 and is obtained when
x = 200 m, which makes y = 800-2(200) = 400 m
let the two other sides be x each
so 2x+y = 800
y = 800-2x
area = xy
= x(800-2x)
= -2x^2 + 800x
Since you rated this grade 10 , I will assume you don't have Calculus, so let's complete the square
area = -2(x^2 - 400x <>+40000-40000</b>)
= -2( (x-200)^2 - 40000)
= -2(x-200)^2 + 80000
the max area is 80,000 m^2 and is obtained when
x = 200 m, which makes y = 800-2(200) = 400 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.