Asked by Max
Im in Chem. but looks like physics.. If a rock climber accidentally drops a 70.5 g piton from a height of 295 meters, what would its speed be just before striking the ground? Ignore the effects of air resistance.
Answers
Answered by
DrBob222
Do you have answers. If you checked my last answer and it was right you can look at this one.
X = distance = Vo*t + 1/2*g*t^2
Vo is 0 and the mass of the pick (piton) doesn't matter. X = 295 m, solve for t = time to strike the ground. Then use
V = Vo + g*t. Again, Vo is 0.
X = distance = Vo*t + 1/2*g*t^2
Vo is 0 and the mass of the pick (piton) doesn't matter. X = 295 m, solve for t = time to strike the ground. Then use
V = Vo + g*t. Again, Vo is 0.
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