What is the maximum height achieved if a 0.800 kg mass is thrown straight upward with an initial speed of 40.0 m·s–1? Ignore the effect of air resistance.
3 answers
Thats what it looks like.. but im taking chem. in college and have never had a physics course, im really lost.
My physics is quite rusty but I believe that would be
V^2 = Vo^2 + 2ax
V^2 will be zero at the top since eventually the pull of gravity will stop the balls upward flight.
0 = (40 m/s)^2 + 2*(-9.8)*x
Solve for x = distance in meters.
V^2 = Vo^2 + 2ax
V^2 will be zero at the top since eventually the pull of gravity will stop the balls upward flight.
0 = (40 m/s)^2 + 2*(-9.8)*x
Solve for x = distance in meters.
alright, thanks lol
1 answer