a=(V^2-Vo^2)/2d = (640^2-0)/2.4=170,667
m/s^2.
V = Vo + a*t
t=(V-Vo)/a = (640-0)/170,667=0.00375 s.
= 3.75 ms.
m/s^2.
V = Vo + a*t
t=(V-Vo)/a = (640-0)/170,667=0.00375 s.
= 3.75 ms.
v = u + at
Where:
v = final velocity (640 m/s)
u = initial velocity (0 m/s inside the barrel, as the bullet starts from rest)
a = acceleration (unknown in this case, as it is not mentioned)
t = time (unknown)
Since the bullet undergoes constant acceleration while inside the barrel, we can use the formula for uniform acceleration:
v^2 = u^2 + 2as
Where:
s = displacement (length of the barrel, 1.20 m)
Assuming the acceleration is constant, we can rearrange the equation to solve for acceleration:
a = (v^2 - u^2) / (2s)
Substituting the given values:
a = (640^2 - 0^2) / (2 * 1.20)
Simplifying the equation:
a = 276800 / 2.40
a = 115333.33 m/s^2
Now, we can use the equation of motion to find the time (t) it takes for the bullet to emerge from the end of the barrel:
640 = 0 + (115333.33)t
Simplifying the equation:
t = 640 / 115333.33
t ≈ 0.0055 seconds
Therefore, it will take approximately 0.0055 seconds (or 5.5 milliseconds) for the bullet to emerge from the end of the barrel after the rifle is fired.