Asked by Chavez
When a bullet leaves a barrel of a rifle, it is moving 640 m/s. If the barrel is 1.20 m long, and if the bullet undergoes constant acceleration while within the barrel, how long after the rifle is fired will the bullet emerge from the end of the barrel?
Answers
Answered by
Henry
a=(V^2-Vo^2)/2d = (640^2-0)/2.4=170,667
m/s^2.
V = Vo + a*t
t=(V-Vo)/a = (640-0)/170,667=0.00375 s.
= 3.75 ms.
m/s^2.
V = Vo + a*t
t=(V-Vo)/a = (640-0)/170,667=0.00375 s.
= 3.75 ms.
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