Question

if a bullet starting from rest leaves the muzzle of a rifle with a speed of 600m/s and the barrel of the rifle is 0.90m long what is the acceleration of the bullet while in the barrel

Answer 1

To find the acceleration of the bullet while in the barrel, we can use the following kinematic equation:

v^2 = u^2 + 2as

where:
v = final velocity of the bullet (600 m/s)
u = initial velocity of the bullet (0 m/s, since it starts from rest)
a = acceleration of the bullet
s = distance traveled in the barrel (0.90 m)

Plugging in the values, we get:

600^2 = 0^2 + 2 * a * 0.90
a = (600^2) / (2 * 0.90)
a = 20000 m/s^2

Therefore, the acceleration of the bullet while in the barrel is 20000 m/s^2.