All of this type can be worked the same way.
1. Write and balance the equation.
NaOH + HCl ==> NaCl + H2O
2. How many mols do you have?
mols = M x L = 0.81M x 0.77L = 0.624
3. Since 1 mol NaOH = 1 mol HCl (from the equation), then mols HCl = mols NaOH.
4. Those three steps work the problem USUALLY, however, the question is what volume of say 0.5 M NaOH will it take? That is mols NaOH = 0.624
M = mols/L. You know mols and M, solve for L.
How many moles of NaOH will it take to neutralize 0.77 L of 0.81 M HCl?
Answer in units of mol
1 answer