Asked by Gabriella
How many moles of NaOH will it take to neutralize 0.77 L of 0.81 M HCl?
Answer in units of mol
Answer in units of mol
Answers
Answered by
DrBob222
All of this type can be worked the same way.
1. Write and balance the equation.
NaOH + HCl ==> NaCl + H2O
2. How many mols do you have?
mols = M x L = 0.81M x 0.77L = 0.624
3. Since 1 mol NaOH = 1 mol HCl (from the equation), then mols HCl = mols NaOH.
4. Those three steps work the problem USUALLY, however, the question is what volume of say 0.5 M NaOH will it take? That is mols NaOH = 0.624
M = mols/L. You know mols and M, solve for L.
1. Write and balance the equation.
NaOH + HCl ==> NaCl + H2O
2. How many mols do you have?
mols = M x L = 0.81M x 0.77L = 0.624
3. Since 1 mol NaOH = 1 mol HCl (from the equation), then mols HCl = mols NaOH.
4. Those three steps work the problem USUALLY, however, the question is what volume of say 0.5 M NaOH will it take? That is mols NaOH = 0.624
M = mols/L. You know mols and M, solve for L.
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