HC2H3O2 = HAc
moles HAc = M x L = 2.6 x 1 = 2.6
Let x = mols OH to be added.
..........HAc + OH^- --> Ac^- + H2O
I.........2.6....0.......0.......0
add..............x...............
C.........-x....-x.......x.......x
E.........2.6-x..0.......x.......x
I don't know what value you are using for pKa.
pH = pKa + log (base)/(acid)
4.28 = pKa + log (x)/(2.6-x)
Solve for x
pH = pKa is done the same way.
Post your work if you get stuck.
How many moles of NaOH must be added to 1.0 L of 2.6 M HC3H5O3 to produce a solution buffered at each pH?
1)pH= 4.28
2)pH=pKa
1 answer
1 answer