Asked by James

If the total positive charge is Q = 1.62×10−6C , what is the magnitude of the electric field caused by this charge at point P, a distance d = 1.53m from the charge? (Figure 1)

Enter your answer numerically in newtons per coulomb.

Answers

Answered by Damon
E = k Q/r^2
direction away from Q since Q is positive
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