Asked by sami
How much positive charge is in 0.8 kg of neon?
The atomic weight (20.1797 g) of neon contains
Avogadro’s number of atoms, with each
atom having 10 protons and 10 electrons. The
elemental charge is 1.602 × 10−19 C and Avogadro’s
number is 6.023 × 1023
.
Answer in units of C.
please help
The atomic weight (20.1797 g) of neon contains
Avogadro’s number of atoms, with each
atom having 10 protons and 10 electrons. The
elemental charge is 1.602 × 10−19 C and Avogadro’s
number is 6.023 × 1023
.
Answer in units of C.
please help
Answers
Answered by
Damon
10 protons * 1.6*10^-19 C per proton
= 16*10^-19 C per atom
16*10^-19 C/atom * 6*10^23 atoms/mol = 96*10^4 C/mol
96*10^4 C/mol * 1 mol/20.2 g = 4.75*10^4 C/gram
4.75*10^4 C/gram * 800 grams = 3801*10^4 = 3.8 *10^7 C
Luckily the neutral atoms have an equal number of electrons to cancel that out.
= 16*10^-19 C per atom
16*10^-19 C/atom * 6*10^23 atoms/mol = 96*10^4 C/mol
96*10^4 C/mol * 1 mol/20.2 g = 4.75*10^4 C/gram
4.75*10^4 C/gram * 800 grams = 3801*10^4 = 3.8 *10^7 C
Luckily the neutral atoms have an equal number of electrons to cancel that out.
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