Asked by Dez

Assuming that gasoline is pure octane (d = 0.703 g/mL), how many metric tons of CO2 are released in a year by an SUV that gets 19 mpg and is driven 17500. miles?
Answered by DrBob222
2C8H18 + 25O2 ==> 16CO2 + 18H2O

17,500 miles/19.2 mpg = ? gallons.
? gallons x 3.785 liters/gallon.
?liters x 1000 = ?mL
?mL x 0.703 g/mL = ? grams
grams octane/molar mass octane = mols octane.
Using the coefficients in the balanced equation, convert mols Octant to mols CO2 produced.
?mols CO2 x molar mass CO2 = grams CO2
?grams x xxx = metric tons CO2.
Answered by Anonymous
8.923 x10 ^-6 MT
Answered by There are 256 x 106 cars in the US. If each car is driven 12,000 miles/year, and averages 20 miles/
There are 256 x 106 cars in the US. If each car is driven 12,000 miles/year, and averages 20 miles/gallon (octane, C8H18, density = 0.780 g/mL), how many tons of CO2 are produced per year?
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