Asked by Melissa
A bicycle racer sprints at the end of a race to clinch a victory. The racer has an initial velocity of 10.0 m/s and accelerates at the rate of 0.600 m/s2 for 7.00 s.
(a) What is his final velocity?
(b) The racer continues at this velocity to the finish line. If he was 300 m from the finish line when he started to accelerate, how much time did he save?
(c) One other racer was 5.00 m ahead when the winner started to accelerate, but he was unable to accelerate and traveled at 10.2 m/s until the finish line. How far ahead of him (in meters and in seconds) did the winner finish?
distance
time
(a) What is his final velocity?
(b) The racer continues at this velocity to the finish line. If he was 300 m from the finish line when he started to accelerate, how much time did he save?
(c) One other racer was 5.00 m ahead when the winner started to accelerate, but he was unable to accelerate and traveled at 10.2 m/s until the finish line. How far ahead of him (in meters and in seconds) did the winner finish?
distance
time
Answers
Answered by
Henry
a. V = Vo * a*t = 10 + 0.6*7 = 14.2 m/s.
b. T = d/r1 - d/r2 = 300/10-300/14.2 =
8.87 s. Saved.
b. T = d/r1 - d/r2 = 300/10-300/14.2 =
8.87 s. Saved.
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