Asked by Joshua
On the graph of f(x) = 8*sin(3pi*x), points P and Q are at consecutive lowest and highest points with P occurring before Q. Find the slope of the line which passes through P and Q.
Slope = ?
I have tried 48/pi and it didn't work
Slope = ?
I have tried 48/pi and it didn't work
Answers
Answered by
Steve
P is where 3pi*x = 3pi/2
P=(1/2,-8)
Q is where 3pi*x = 5pi/2
Q=(5/6,8)
so, the slope of PQ is 16/(1/3) = 48
P=(1/2,-8)
Q is where 3pi*x = 5pi/2
Q=(5/6,8)
so, the slope of PQ is 16/(1/3) = 48
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