Asked by Jesse
A computerized spin balance machine rotates a 35-inch-diameter tire at 400 revolutions per minute.
(a) Find the road speed (in miles per hour) at which the tire is being balanced. (Round your answer to two decimal places.)
(b) At what rate should the spin balance machine be set so that the tire is being tested for 50 miles per hour? (Round your answer to two decimal places.)
(a) Find the road speed (in miles per hour) at which the tire is being balanced. (Round your answer to two decimal places.)
(b) At what rate should the spin balance machine be set so that the tire is being tested for 50 miles per hour? (Round your answer to two decimal places.)
Answers
Answered by
Steve
2π*35*400 = 28000π in/min
Now just convert that to mi/hr.
for 50mi/hr, just take the fraction needed to get 50. That is, if the answer to (a) is 100 mi/hr, just take 50/100 of 400rpm to get the balancing speed.
Now just convert that to mi/hr.
for 50mi/hr, just take the fraction needed to get 50. That is, if the answer to (a) is 100 mi/hr, just take 50/100 of 400rpm to get the balancing speed.
Answered by
Damon
circumference = pi d = 110 inches = 9.16 feet
it does 400 circumferences /minute
9.16 ft * 400 = 3665 feet/minute
3665 feet/min * 60 min/hr * 1 mi/5280 ft
= 41.65 miles/hr
400 * (50/41.65) = 480.19 rpm
it does 400 circumferences /minute
9.16 ft * 400 = 3665 feet/minute
3665 feet/min * 60 min/hr * 1 mi/5280 ft
= 41.65 miles/hr
400 * (50/41.65) = 480.19 rpm
Answered by
Steve
dang - go with Damon again. I used a 35" radius.
Note to self: read twice, type once.
Note to self: read twice, type once.
Answered by
Damon
Thanks For your help with the 7 letter problem ! It was driving me crazy.
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