8 Quarters + 3 Dimes + 7 Nickels = 21 coins
he uses 16 coins
21 - 16 = 5
he used 8 Quarters, 3 Dimes and 5 Nickels
therefore he has 2 Nickels left
a. 1 dime, 1 nickel
b. 1 dime, 1 quarter
c. 1 nickel, 1 quarter
d. 2 quarters
e. 2 nickels
please answer and explain
he uses 16 coins
21 - 16 = 5
he used 8 Quarters, 3 Dimes and 5 Nickels
therefore he has 2 Nickels left
18 coins to start and uses 16, 18-16=2
So 2 coins left over
8 quartes = 2.00
2 dimes = 0.20
6 nickels = 0.30
8+6+2=16 2.00+0.30+0.20 = 2.50
John initially had:
8 quarters = 8 * $0.25 = $2.00
3 dimes = 3 * $0.10 = $0.30
7 nickels = 7 * $0.05 = $0.35
The total value of his initial coins is $2.00 + $0.30 + $0.35 = $2.65
He used 16 coins worth $2.50 to buy tacos.
Now, let's find out which coins remain in the change holder:
Total value of coins he had initially - Total value of coins used to buy tacos = Value of remaining coins
$2.65 - $2.50 = $0.15
Now we need to determine the composition of the remaining coins based on their value.
In this case, the only possible combination of coins that equals $0.15 is:
1 dime ($0.10) + 1 nickel ($0.05) = $0.15
So, the correct answer is option a. 1 dime, 1 nickel.
To solve this problem, you could also list all the possible combinations and check which one adds up to $0.15. However, that would be time-consuming and more prone to errors, especially if there are more coins involved. By calculating the total value and subtracting the value of the coins used, we can quickly find the composition of the remaining coins.