Asked by Andy G
The game commission introduces 100 deer into newly acquired state game lands. the population N of the herd is modeled by N=(20(5+3t))/1+0.04t t>/=0
where t is the time in years
a. find the population when t=5, t=10, and t=25
b. what is the limiting size of the herd as time increases?
where t is the time in years
a. find the population when t=5, t=10, and t=25
b. what is the limiting size of the herd as time increases?
Answers
Answered by
Anonymous
12
Answered by
Reiny
you must mean
N = 20(5+3t)/(1+.04t)
plug in t = 5
N = 20(5+15)/(1 + .04(5))
= 400/1.02
= 2000
Do the others likewise.
as t ---> large
n = (100 + 60(large))/(1 + .04 large)
= appr 60large/.04large
= appr 60/.04 ---> 1500
the limiting size = 1500
e.g. let t = 100,000
N = 20(300005)/(1 + 4000) = 1500.025
N = 20(5+3t)/(1+.04t)
plug in t = 5
N = 20(5+15)/(1 + .04(5))
= 400/1.02
= 2000
Do the others likewise.
as t ---> large
n = (100 + 60(large))/(1 + .04 large)
= appr 60large/.04large
= appr 60/.04 ---> 1500
the limiting size = 1500
e.g. let t = 100,000
N = 20(300005)/(1 + 4000) = 1500.025
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