Question

A 0.887g sample of a mixture of nacl and kcl is dissolved in water , and the solution is then treated with an excess of agn03 to yield 1.913g of agcl. Calculate the percent by mass of nacl in the mixture

1.913/143g/mol = 0.01337
who helps me
0.887/58.44g/mol = 0.01517

Percent by mass of NaCl = (0.01517/0.01337) x 100 = 113.3%

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