0.887g sample of a mixture of nacl and kcl is dissolved in water. The solution is then treated with an excess agn03 to yield 1.1930of agn03. Calculate the percent by mass of each compound in the mixture
agcl = 143g/mol
1.1930/143 = 0.001337 m agcl
x/58g/mol + (0.8870g -x) + y/74g/mol = 0.001337
The right answer 87.7%
Who helps me step by step
1 answer