Asked by kaa
You want to make a rectangular box, open at the top, by cutting the same size square corners out of a rectangular sheet of cardboard and then folding up the sides. The cardboard measures 10 in. by 12 in. What are the dimensions of the box that will have greatest volume if the possible corner cuts measure 1 in., 2 in., 3 in., or 4 in.?
Answers
Answered by
Steve
well, the volume is width * length * height (x)
v = (10-2x)(12-2x)(x)
now plug in x=1,2,3,4 and see which gives the greatest volume
v = (10-2x)(12-2x)(x)
now plug in x=1,2,3,4 and see which gives the greatest volume
Answered by
kaa
a.9 in. by 12 in. by 1 in.
b.3 in. by 6 in. by 4 in.
c.7 in. by 10 in. by 2 in.
d.5 in. by 8 in. by 3 in.
c?
Answered by
Steve
Nope. Think about it. Since the two original dimensions are 8x10, after the cuts, the base of the box will be
8x10
6x8
4x6
2x4
You cannot even get (c) by cutting equal squares from all corners.
8x10
6x8
4x6
2x4
You cannot even get (c) by cutting equal squares from all corners.
Answered by
nene
is it a?
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