Asked by Lucas
A bullet whose mass is 0.0015kg leaves a 5kg leaves a 5kg rifle at a muzzle velocity of 800 m/s. It strikes a 7kg block of wood and becomes embedded in it.
After the bullet hits the rock, what is the speed of the bullet/ block system?
After the bullet hits the rock, what is the speed of the bullet/ block system?
Answers
Answered by
Steve
preserve momentum, so
(0.0015)(800) = (0.0015+7)v
(0.0015)(800) = (0.0015+7)v
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