100,000J of heat is added to a 2.0KG of ice at -8degrees C. How much ice melts?

Answer 1

The heat of fusion is 80 cal/g = 335 J/g
The specific heat of ice 2.11 J/g*degC

To heat the ice to 0 C requires
2000 g * 8 C *2.11 J/c*C = 33,760 J

There is more than enough heat to melt all of the ice.