10 grams of ice at 0 degree centigrade absorbs 5460 joules of heat to melt and change itno water at 50 degree centigrade.calculate the specific latent heat of fusion of ice?

Answer 1

heat=heatmeltingIce+heatRisingTempWater
5640=10*Lf + 10*cwater*(50-0)
put in the specific heat of water cw, in joules/gram-C, and solve for heat of fusion, Lf.