heat lost by metal + heat gained by H2O = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for specific heat metal which is the only unknown in th equation. BTW, centigrade is out; celsius is in.
50 gram of steel at 100 degree centigrade is addae to 100grame of water at 30 degree centigrade the resultant temperature is 35 degree centigrade find the specific heat of metel
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