...AgCl(s) ==> Ag^+(aq) + Cl^-(aq)
I..solid.......0...........0
E..solid.....1.35E-5.....1.35E-5
Ksp = (Ag^+)(Cl^-) = (1.35E-5)^2 = ?
10.0 mL of 0.05 M AgNO3 and 10.0 mL 0.05 M NaCl are combined in a test tube and a precipitate of AgCl forms. After the precipitate is centrifuged down, the remaining solution (called the supernatant) is tested for the concentration of Ag+ ion. The concentration is found to be 1.3x10^-5. Calculate the Ksp of AgCl from this information. Show work please. Thanks!
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