Asked by annonomus

Silver nitrate (AgNO3) reacts with sodium
chloride as indicated by the equation
AgNO3 + NaCl → AgCl + NaNO3 .
How many grams of NaCl would be required
to react with 132 mL of 0.719 M AgNO3
solution?
Answer in units of grams.
Answered by DrBob222
AgNO3 + NaCl → AgCl + NaNO3
millimoles AgNO3 = 132 mL x 0.719 = 94.9
millimols NaCl needed = 94.9 x (1 mol NaCl/1 mol AgNO3) = 94.9
mols NaCl = 0.0949.
grams NaCl = mols NaCl x molar mass NaCl = ?
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