Continue #2: So it says to : Calculate the mass of ammonia, NH3, that can be produced.
Can someone explain how to derive to the answer? Please
1.) what mass of zinc is needed to completely react with 4.00 g of silver nitrate?
2.) If excess ammonium sulfate reacts with 22.5 g of calcium hydroxide according to the following unbalanced chemical equation:
(NH4)2 SO4 + Ca (OH)2 → CaSO4 + NH3 + H2O
Now, how do I go from here?
3 answers
TEST VERY SOON
1.
Zn + 2AgNO3 ==> Zn(NO3)2 + 2Ag
mols AgNO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols AgNO3 to mols Zn.
Now convert mols Zn to grams Zn. g Zn = mols Zn x atomic mass Zn.
2. The balanced equation is as follows:
(NH4)2SO4 + Ca(OH)2 → CaSO4 + 2NH3 + 2H2O
mols Ca(OH)2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols NH3. Then convert mols NH3 to grams.
g NH3 = mols NH3 x molar mass NH3.
Zn + 2AgNO3 ==> Zn(NO3)2 + 2Ag
mols AgNO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols AgNO3 to mols Zn.
Now convert mols Zn to grams Zn. g Zn = mols Zn x atomic mass Zn.
2. The balanced equation is as follows:
(NH4)2SO4 + Ca(OH)2 → CaSO4 + 2NH3 + 2H2O
mols Ca(OH)2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols NH3. Then convert mols NH3 to grams.
g NH3 = mols NH3 x molar mass NH3.