Asked by Anonymous

Nitric acid and zinc react to form zinc nitrate, ammonium nitrate, and water.

4Zn(s) + 10HNO3(aq) → 4Zn(NO3)2(aq) + NH4NO3(aq) + 3H2O(l)

A. How many atoms of zinc react with 1.49g HNO3?
B. Calculate the number of grams of zinc that must react with an excess of HNO3 to form 29.1g NH4NO3
Answered by DrBob222
Convert 1.49 g HNO3 to moles. That Is Grams divided by molar mass.
Using the coefficients in the balance chemical equation convert moles nitric acid to moles of zinc.
To calculate atoms of zinc remember that one mole of zinc contains 6.02E23 atoms.

B is done the same way as A. Remember that after finding moles you convert to grams by grams = moles times molar mass
.
Answered by Anonymous
5.70E22
Answered by Anonymous
A) 5.695E21
B)95.07
Answered by Jack Anderson
These are great answers!
Answered by Celya
Le cuivre est un métal relativement peu réactif. Il ne réagit pas au contact de la plupart des acides, sauf l’acide nitrique.

Cu(s) + 4HNO3(aq) ---> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

Quelle masse de NO2 obtient-on quand on fait réagir 54,4g de Cu avec 125g de HNO3 ?
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