1. To find the mean, median, mode, and range of the data set, first arrange the altitudes in ascending order: -52, -36, -36, -27, -23, -17, -9, -8.
Mean: Add all the altitudes and divide by the total number of data points:
(-52 + -36 + -36 + -27 + -23 + -17 + -9 + -8) / 8 = -208 / 8 = -26
Median: The median is the middle value when the data is arranged in ascending order. Since there are 8 data points (an even number), the median is the average of the two middle values (-27 and -23):
(-27 + -23) / 2 = -50 / 2 = -25
Mode: The mode is the value that appears most frequently in the data set. In this case, the mode is -36 because it appears twice.
Range: The range is the difference between the highest and lowest values in the data set:
-8 - (-52) = -8 + 52 = 44
So, the mean is -26, the median is -25, the mode is -36, and the range is 44.
2. Given the data 21, 13, 13, 37, 13, 23, 25, 15:
a. The outlier in the data is 37, as it is significantly higher than the rest of the data points.
b. To find the mean with the outlier, add all the data points and divide by the total number of data points:
(21 + 13 + 13 + 37 + 13 + 23 + 25 + 15) / 8 = 150 / 8 = 18.75
c. To find the mean without the outlier, remove the outlier from the data set and perform the same calculations:
(21 + 13 + 13 + 13 + 23 + 25 + 15) / 7 = 113 / 7 = 16.14
3. For this question, the data related to how each student in a class traveled to school in the morning is not given. Please provide the data so I can create a frequency table for you.
1.What are the mean,median,mode and range of the data set given the altitude of lakes in feet:-9,-36,-23,-8,-17,-52,-27,and-36?
2.Given the data 21,13,13,37,13,23,25,15
a.What is the outlier in the data?
b.what is the mean with the outlier?
c.what is the mean without the outlier?
3.Which frequency table represents the set of data below related how each student in a class traveled to school in the morning? And if there is anyone who knows the rest of the answers that would be helpful thank you. PLEASE HELP ME
1 answer