1. Using the equation for Charle's law, find an expression for T1

Question

2. If the temperature of a certain gas is tripled from its original value while keeping the pressure of the gas fixed, what is the new volume of the gas compared to its original volume?

Answer 1

Charles' Law is V1/T1 = V2/T2. Solve for T1.
V1T2 = V2T1
T1 = V1T2/V2

Be careful with #2. Tripled with respect to degree K or tripled with respect to degree C.
V1T2 = V2T1 or
V1/V2) = (T1/T2) so if you use degrees K, as you must in Charles' Law, then when you triple T1 to make the new temperature T2,then you will triple the volume so it is now 3V1 for V2. But that is NOT true if you triple T in degrees C. I'll leave that for you to calculate; e.g., suppose you have a volume of 100 cc for V1 at a T1 of 100 C and you want to know the volume V2 when T2 is 300 C. Try that and you will not get 300 cc for V2 BECAUSE you're going from a T1 temperature of 273 + 100 = 373 K.T2 then is 273 + 300 = 573 . You see 573 K is not three times 373 K so the volume will not be tripled either.

Answer 2

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