Oh I forgot! Thank you again oobleck, in advance! I greatly appreciate ALL the help you’ve given me the past few days! It’s been very helpful for me during this class! Again thank you so so so much! :)
-Justin
1. The graph of f ′′(x) is continuous and decreasing with an x-intercept at x = –3. Which of the following statements must be true?
A. The graph of f is always concave down.
B. The graph of f has an inflection point at x = –3.
C. The graph of f has a relative minimum at x = –3.
D.None of these is true.
2. A particle moves on the x-axis so that its position is continuous on the interval [3, 13] with some of its values for its velocity v(t) given in the table below. Use a trapezoidal sum with 4 intervals to approximate the total distance the particle travelled in the time interval [3, 13].
t 3 7 10 12 13
v(t) 5 9 14 18 24
A.277.50
B. 138.75
C.115.50
D. 87.50
3. The function f is continuous on the interval [3, 11] with some of its values given in the table below. Use the data in the table to approximate f ′(9).
x 3 5 8 10 11
f(x) –4 4 10 16 20
A.8
B.13
C.16
D.None of these
4. F of x equals the integral from 1 to x of the natural logarithm of t squared. Use your calculator to find F ′(3).
A. 2.197
B.2.079
C. 1.099
D. 0.693
5. The table of values below shows the rate of oil consumption in gallons per minute at selected time intervals from t = 0 to t = 12.
Using a left Riemann sum with 5 subintervals estimate the total amount of oil consumed in that time interval. Give your answer correct to 1 decimal place.
x 0 2 5 7 11 12
f(x) 7 4.0 3.2 2.2 1.6 1
Fill in the blank:_________
6. The graph of f ′ (x), the derivative of f(x), is continuous for all x and consists of five line segments as shown below. Given f (5) = 10, find the absolute minimum value of f (x) over the interval [0, 5].
graph of line segments increasing from x equals negative 4 to x equals negative 3, decreasing from x equals negative 3 to x equals 0, increasing from x equals 0 to x equals 3, constant from x equals 2 to x equals 4 and decreases from x equals 4 to x equals 5. x intercepts at x equals negative 4, x equals 0, x equals 5
Graph image: learn.flvs.net/webdav/assessment_images/educator_calculus_v14/08_00_q08.gif
A. 3
B. 0
C. 7
D. 17
2 answers
#1.
A false, if f" is ever positive
B true
C false. Consider y = -(x+3)^3
#2.
Surely by now you know how to sum up these areas! You know the area of a trapezoid is (B+b)/2 * h, so
(5+9)/2 * (7-3) + (9+14)/2 * (10-7) + (14+18)/2 * (12-10) + (18+24)/2 * (13-12) = 231/2
#3. f'(9) is approximately the slope of the line joining (8,f(8)) and (10,f(10)),
which is (16-10)/(10-8) = 3
#4. See your previous post. You still haven't made it clear. Ditch the words and write it as math.
#5. Come on. I've done several Riemann sums for you. The area of a rectangle is width * height! So just add 'em up.
#6. Cannot login to your course web site.
So, I can't see your graph. But it appears that f'(x) is never negative, which means that f(x) is increasing over the whole interval [-4,5]. So clearly f(x) is a minimum at x=4, where the area below the graph is zero.
It would have been easier if you had just given the coordinates of all the vertices of the graph of f'(x). Lots less typing, and no confusion.
A false, if f" is ever positive
B true
C false. Consider y = -(x+3)^3
#2.
Surely by now you know how to sum up these areas! You know the area of a trapezoid is (B+b)/2 * h, so
(5+9)/2 * (7-3) + (9+14)/2 * (10-7) + (14+18)/2 * (12-10) + (18+24)/2 * (13-12) = 231/2
#3. f'(9) is approximately the slope of the line joining (8,f(8)) and (10,f(10)),
which is (16-10)/(10-8) = 3
#4. See your previous post. You still haven't made it clear. Ditch the words and write it as math.
#5. Come on. I've done several Riemann sums for you. The area of a rectangle is width * height! So just add 'em up.
#6. Cannot login to your course web site.
So, I can't see your graph. But it appears that f'(x) is never negative, which means that f(x) is increasing over the whole interval [-4,5]. So clearly f(x) is a minimum at x=4, where the area below the graph is zero.
It would have been easier if you had just given the coordinates of all the vertices of the graph of f'(x). Lots less typing, and no confusion.
2 answers