are those degrees ?
I will assume you are familiar with the basic identities.
1 + tan^2 (5°) - csc^2 (85)
= sec^2 (5) - csc^2(85
but sec Ø = csc(90-Ø)
so sec(5) = csc(85)
so continuing from above
= csc^2(85) - csc^2(85)
0
1 + tan^2 (5) - csc^2 (85) = ?
Would this equal 0
could someone explain this to me and the correct answer?
7 answers
Correct if you work in degrees.
For details, see response:
http://www.jiskha.com/display.cgi?id=1299028595
For details, see response:
http://www.jiskha.com/display.cgi?id=1299028595
tan 5=sin5/cos5=cos85/sin85
now, since they are the same angles, I will call that angle T
1+cos^2t/sin^t -1/sin^2t=
(sin^2+cos^2 -1)/sin^2t=
0
check that.
now, since they are the same angles, I will call that angle T
1+cos^2t/sin^t -1/sin^2t=
(sin^2+cos^2 -1)/sin^2t=
0
check that.
yes, they are degrees, thank you soo much!
geepers, three folks knew how to do it. I bet millions of others have laboured through it also.
And all within one minute of each other !
Good
1 answer