1. Suppose that 10.2 mL of 0.0512 M NaOH were required to titrate a sample of unkown acid. How many moles of NaOH were used?
3 answers
mols = M x L = ?
only part of my answer was posted. The real question is: Assuming that the unknown acid sample in question 1 has a mass of 0.177g, what is the molar mass of the unknown? I tried moles = Grams/Molar Mass, but the answer is saying incorrect.
I don't see any answer you posted; I see only questions.
NaOH + HA ==> NaA + H2O
1 mol NaOH = 1 mol HA so
mols NaOH from above = mols HA.
Then mols = grams/molar mass or
molar mass = grams/mols. If you did g/mols, I suggest you post your work and let us look at it.
NaOH + HA ==> NaA + H2O
1 mol NaOH = 1 mol HA so
mols NaOH from above = mols HA.
Then mols = grams/molar mass or
molar mass = grams/mols. If you did g/mols, I suggest you post your work and let us look at it.
1 answer