In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL of DI water and titrate the sample with 0.10 M NaOH. Calculate the volume (to the nearest mL) of NaOH required to reach the equivalence point.

Question

In an experiment, you dissolve 0.30 g of KHP (MM = 204.22 g/mol) in 20 mL of DI water and titrate the sample with 0.10 M NaOH.  Calculate the volume (to the nearest mL) of NaOH required to reach the equivalence point. 
IS it a) 3 b)15 c)20 d)30 e)100

I have done MV=MV  (0.3/204.22)(20)=(0.10)(V) and have gotten 0.2938 Which is nowhere close to any of these answers. I don't know what I am doing wrong. Please help.

DrBob222 · Answer

This is not a dilution problem. mols KHP = grams/molar mass = ? mols NaOH = mols KHP M NaOH = mols NaOH/L NaOH Solve for L NaOH and convert to mL.