1). Solve the following simultaneous equations.

a) 3/x + 5/y = 4, 9/x + 4/y = 5
b) 3x +y - 1/2 = 2x -1/3 = 5x - 2y + 1/5

1 answer

It'd be nice to have some of your work to look at, eh?

3/x + 5/y = 4
9/x + 4/y = 5
It gets messy to try and solve for x or y, so solve for 1/x instead.
1/y = (4-3/x)/5
thus,
9/x + 4/5 (4-3/x) = 5
45/x + 16 - 12/x = 25
33/x = 9
1/x = 9/33 = 3/11
so, x = 11/3
now plug in to find y.

The second problem looks like you'll have to solve two equations:
3x +y - 1/2 = 2x -1/3
5x - 2y + 1/5 = 2x -1/3

best to clear the fractions first, then just solve the usual ways.
Similar Questions
    1. answers icon 2 answers
  1. 1)solve the equation log(6x-2)-1=log(x-3)2)evaluate without using mathematical tables,the expression 2log 5-12log 16+2 log 40
    1. answers icon 3 answers
  2. 1. Solve the following simultaneous equations:log2 xy = 7 log2 (x^2/y) = 5 2. If log y x =a and log z x=b where x is not equal
    1. answers icon 5 answers
  3. how do i solve two step equations?Do you mean two equations in two unknowns? The method of substitution is one way. There is a
    1. answers icon 0 answers
more similar questions