#1. no calculator? It will be in 1st quadrant.
#2. how long is the court? The angle is x where tan(x) = 2.44/(court length)
1.Solve sin ¥è = 0.95 for -90¨¬ ¡ ¥è ¡ 90¨¬.
2.A volleyball player spikes the ball from a height of 2.44 meters. Assume that the path of the ball is a straight line. To the nearest degree, what is the maximum angle, ¥è, at which the ball can be hit and land within the court? (Enter only the number.)
If you could give me steps that are pretty simple to follow to get the correct answer that would be great. I'm just really confused. Thank You.
1 answer
1 answer