1)
2x^2 -24 x + 40 = 0
x^2 - 12 x + 20 = 0
(x-2)(x-10) = 0
x = 2
or
x = 10
1.) Solve for x. 2x(x - 12) = -40
2.) Solve for x. 3x2 + 2x = 12 - 7x
3.) Simplify the expression. 8sqrt[-63]
4.) Find the absolute value of the complex number. Abs Val [7 + 24i]
5.) Simplify the expression. [4 - 7i] + [2 + 3i]
Thank you so much!! :)
5 answers
3x2 + 2x = 12 - 7x
3 x^2 + 9 x - 12 = 0
x^2 + 3 x - 4 = 0
(x+4)(x-1) = 0
x = 1
or
x = -4
3 x^2 + 9 x - 12 = 0
x^2 + 3 x - 4 = 0
(x+4)(x-1) = 0
x = 1
or
x = -4
8sqrt[-63]
not much I can do but put an i in
8 i sqrt 63
not much I can do but put an i in
8 i sqrt 63
7 + 24i
r = sqrt (49 + 576) = 25
r = sqrt (49 + 576) = 25
[4 - 7i] + [2 + 3i]
just add
6 -4i
just add
6 -4i