Question 1
Select all the statements that are true for the linear equation \(y = 0.03x + 0.55\).
True Statements:
- y = 0.03x + 0.55 represents the linear equation (True as it's given in the question).
- The cost of a loaf of bread in 1990 was $0.70. (Needs a data reference; check context to verify if true).
- (27, 1.48) is a solution to the linear equation (Substituting \(x = 27\), \(y = 0.03(27) + 0.55 = 0.81 + 0.55 = 1.36\) — so false).
- The cost of a loaf of bread in 2015 was $1.50. (Needs a data reference; check context to verify if true).
- (5, 0.7) is a solution to the linear equation (Substituting \(x = 5\), \(y = 0.03(5) + 0.55 = 0.15 + 0.55 = 0.70\) — so true).
- A loaf of bread cost $0.55 in 1985. (Needs a data reference; check context to verify if true).
Summary for Question 1:
- True: Statement 1, Statement 5 (and possibly others depending on context).
- False: Statement 3.
Question 2
Which equations have the solution set of {12, −3}?
True Equations:
-
(4x - 2)(x + 3) = 0
- Roots: \(4x - 2 = 0 \Rightarrow x = 0.5\) (not a solution).
- \(x + 3 = 0 \Rightarrow x = -3\) (solution).
- Not correct.
-
(x + 12)(x + 3) = 0
- Roots: \(x + 12 = 0 \Rightarrow x = -12\) (not a solution).
- \(x + 3 = 0 \Rightarrow x = -3\) (solution).
- Not correct.
-
(3x - 6)(3x - 6) = 0
- Root: \(3x - 6 = 0 \Rightarrow x = 2\) (not a solution).
- Not correct.
-
(6x - 3)(4x + 12) = 0
- Roots: \(6x - 3 = 0 \Rightarrow x = 0.5\) (not a solution).
- \(4x + 12 = 0 \Rightarrow x = -3\) (solution).
- Not correct.
-
(x - 12)(x + 3) = 0
- Roots: \(x - 12 = 0 \Rightarrow x = 12\) (solution).
- \(x + 3 = 0 \Rightarrow x = -3\) (solution).
- Correct.
-
(x − 12)(x − 3) = 0
- Roots: \(x − 12 = 0\) (solution).
- \(x - 3 = 0 \Rightarrow x = 3\) (not a solution).
- Not correct.
-
(4x + 2)(x + 3) = 0
- Roots: \(4x + 2 = 0 \Rightarrow x = -0.5\) (not a solution).
- \(x + 3 = 0 \Rightarrow x = -3\) (solution).
- Not correct.
Summary for Question 2:
- True: (x - 12)(x + 3) = 0
Question 3
Which of the following ordered pairs is part of the solution set for the equation?
Without the actual equation or image, I can't assess accurately, but you would typically substitute the ordered pairs into the equation provided and see if they satisfy the equation. Check each ordered pair against the equation to determine if it holds true.
Summary:
- To answer the questions accurately, each must be verified against the given equations and information.