1. net ionic equation for the reaction between silver nitrate and the arsenate ion
I got:
3Ag (+) + AsO4 ---> Ag3AsO4
2. net ionic equation for the precipitation of copper hexacyanoferrate (II).
I got:
2Cu (2+) + [Fe(CN)6] ---> Cu2 [Fe(CN6)]
Can someone please check and see if I did these correctly. If not, can you please example how/ what I am doing wrong.
4 answers
The total electrical charge on the left side of a chemical equation must be equal to the total electrical charge on the right side. That is not the case on either chemical equation as you typed it.
The Ag3AsO4 equation is ok if we assume the ---(which looks like an arrow with the >) is actually the charge on the arsenate ion. You can write AsO4^3- and that way we don't confuse it with the arrow.
3Ag^+1 + AsO4^3- ==> Ag3AsO4(s)
3Ag^+1 + AsO4^3- ==> Ag3AsO4(s)
Oh sorry I forgot to write the charges.
For then for the second one,
it is supposedly look like this?
2Cu (2+) + [Fe(CN)6]^(4-) ==> Cu2 [Fe(CN6)]
would that make this ionic equation correct?
For then for the second one,
it is supposedly look like this?
2Cu (2+) + [Fe(CN)6]^(4-) ==> Cu2 [Fe(CN6)]
would that make this ionic equation correct?
That looks ok to me.
1 answer