1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s)
[N2O] = 0.383 M
I know I posted a similar question but I am having trouble with this one as well. Should I do 1/1.75 first and then add 1.10e-3 and then multiply by 1852?
3 answers
P.E.M.D.A.S
So first I did multiplication (1.10e-3)(1852) and then divided 1/1.75 and then added and I cant get the answer.
1/[N2O] = 1/(1.75M) + (1.10E-3M^-1 S^-1)(1852s)
= 0.5714/M + 2.0372/M
= 2.6086/M
So, [N2O] = M/2.6086 = 0.3833M
You can't just divide by 1.75 since it's not a multiplier of the other term. Keep careful track of the units to avoid such mistakes.
= 0.5714/M + 2.0372/M
= 2.6086/M
So, [N2O] = M/2.6086 = 0.3833M
You can't just divide by 1.75 since it's not a multiplier of the other term. Keep careful track of the units to avoid such mistakes.