1 mole of element x has mass, 0.444 times the mass of 1mole of element Y. one average atom of element x has mass 2.96 times the mass of one atom of ^12c. what is the atomic wt. of Y?

Answer 1

X = 0.444*Y
X = 2.96*12
Y = ?

Answer 2

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Answer 3

Sorry, I made a mistake in my previous response. Let's correct it.

Given:
1 mole of element X has a mass that is 0.444 times the mass of 1 mole of element Y.
An average atom of element X has a mass that is 2.96 times the mass of one atom of ^12C.

Let's assume the atomic weight of Y is A, and the atomic weight of X is B.

From the first statement, we have:
B = 0.444A (equation 1)

From the second statement, we have:
B/M(Na) = 2.96 (equation 2)

Where M(Na) is the molar mass of ^12C.

We can solve this system of equations to find the atomic weight of Y (A).

Substituting equation 1 into equation 2:

0.444A/M(Na) = 2.96

Simplifying:

A(M(Na)) = 2.96/0.444

A(M(Na)) = 6.667

A = 6.667/M(Na)

Now, the molar mass of ^12C (M(Na)) is 12 g/mol.

Substituting the value of M(Na):

A = 6.667/12

A ≈ 0.555 g/mol

Therefore, the atomic weight of Y is approximately 0.555 g/mol.