1) log(9 – x) – log(6 + x) = 1

Question

2) e^2x + e^2x = 1
3) 2e^6x + e^6x = b

Answer 1

log [(9-x)/(6+x) ] = 1
if that is log base ten then
(9-x)/(6+x) = 10^1 = 10

9-x = 60 + 10 x
solve for x

Answer 2

e^(4x^2) = 1
ln (e^4x^2) = ln 1
4 x^2 = 0
x = 0

Answer 3

3 e^6x = b
e^6x = (b/3)
6x = ln b - ln 3

x = (1/6 ) (ln b/3)