1.
a.)
Vf=Vi +at
Where
Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s
Solve for Vf:
Vf=0m/s +(0.5m/s^2)*(12s)
Vf=6m/s
b.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=10s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2
d=0 +25m
d=25m
c.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=40s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2
d=0 +400m
d=400m
d.)
Plot distance Vs velocity
x axis =displacement and y=velocity
2.
****Plot distance on the x-axis and time (distance/velocity) on the y-axis.
***Remember, Bryce only has to travel 800m.
a.)
d=r*t
Where
r=velocity
t=?
and
d=displacement.
Bryce
d=800m
r=18m/s
t=?
800=18m/s*t
t=800m/18m/s
t=44.4s
Ally
d=1,000m
r=23m/s
t=?
1,000m=23m/s*t
t=1,000m/23m/s
t=43.5s
Ally wins.
b.)
Bryce wins the race in 43.4s. How far is Ally from the finish line when Bryce reaches the finish line?
d=18 m/s*43.4s
d1=781.2m
Total distance=d1+d2=781.2m + 200m=981.2m
1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.
1. Jasmine rode a horse down a path headed north. she started from rest and then accelerated at 0.5 m/s2 for 12 seconds and then travelled at a constant speed for 28 seconds.
a.) what was her velocity after 12 seconds?
b.) what was jasmines displacement after 10 seconds?
c.) how far did Jasmine travel during her 40 s ride?
d.) draw a velocity time graph for her motion
2. Bryce can ride his bicycle at an average speed of 18 m/s and Ally rides with an average speed of 23 m/s. ally gives bryce a 200 m Headstart in a 1 km (1000m) race. use a distance time graph to solve the following questions:
a.) who wins the race? explain your answer
b.) how many meters separate the 2 cyclists at the end of the race?
3 answers
Typo correction. Look for ^&***" for correction .
1.
a.)
Vf=Vi +at
Where
Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s
Solve for Vf:
Vf=0m/s +(0.5m/s^2)*(12s)
Vf=6m/s
b.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=10s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2
d=0 +25m
d=25m
c.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=40s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2
d=0 +400m
d=400m
d.)
Plot distance Vs velocity
x axis =displacement and y=velocity
2.
****Plot distance on the x-axis and time (distance/velocity) on the y-axis.
***Remember, Bryce only has to travel 800m.
a.)
d=r*t
Where
r=velocity
t=?
and
d=displacement.
Bryce
d=800m
r=18m/s
t=?
800=18m/s*t
t=800m/18m/s
t=44.4s
Ally
d=1,000m
r=23m/s
t=?
1,000m=23m/s*t
t=1,000m/23m/s
t=43.5s
Ally wins.
b.)
^&***" Ally wins the race in 43.4s. How far is Bryce from the finish line when Ally reaches the finish line?" ***^&
d=18 m/s*43.4s
d1=781.2m
Total distance=d1+d2=781.2m + 200m=981.2m
1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.
1.
a.)
Vf=Vi +at
Where
Vf=?
Vi=0m/s
a=0.5m/s^s
t=12s
Solve for Vf:
Vf=0m/s +(0.5m/s^2)*(12s)
Vf=6m/s
b.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=10s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(10s)^2
d=0 +25m
d=25m
c.)
d=Vi*t + 1/2at^2
Where
d=?
Vi=0m/s
a=0.5m/s^s
t=40s
Solve for d:
d=0m/s*(12s) + 1/2(0.5m/s^2)(40s)^2
d=0 +400m
d=400m
d.)
Plot distance Vs velocity
x axis =displacement and y=velocity
2.
****Plot distance on the x-axis and time (distance/velocity) on the y-axis.
***Remember, Bryce only has to travel 800m.
a.)
d=r*t
Where
r=velocity
t=?
and
d=displacement.
Bryce
d=800m
r=18m/s
t=?
800=18m/s*t
t=800m/18m/s
t=44.4s
Ally
d=1,000m
r=23m/s
t=?
1,000m=23m/s*t
t=1,000m/23m/s
t=43.5s
Ally wins.
b.)
^&***" Ally wins the race in 43.4s. How far is Bryce from the finish line when Ally reaches the finish line?" ***^&
d=18 m/s*43.4s
d1=781.2m
Total distance=d1+d2=781.2m + 200m=981.2m
1,000m-981.2m=18.8m=19.0m is the distance that separates them when the race ends.
Thank u so much :)
1 answer