m = 2^x
n = 4^y = 2^(2y)
mn = 2^(x+2y)
do the others in like wise, using the properties of logs and exponents.
Come back with your work if you get stuck.
1. Given log2(m) = x, log4(n) = y
What is mn?
2. Given log5(m) = x, log√5(n) = y
What is mn?
3. Given log2(m^2) = x, log8(√n) = y
What is mn?
2 answers
I'll do #2, you do the rest the same way:
log5 m = x <-----> 5^x = m
log√5 n = y <-----> √5^y = n
mn = 5^x * (√5)^y
= (√5)^(2x) * √5^y
= (√5)^(2x+y)
log5 m = x <-----> 5^x = m
log√5 n = y <-----> √5^y = n
mn = 5^x * (√5)^y
= (√5)^(2x) * √5^y
= (√5)^(2x+y)