f:j = 3:4
j:s = 7:6
LCM(4,7) = 28, so
f:j = 21:28
j:s = 28:24
f:j:s = 21:28:24
so, f:s = 21:24 = 7:8
total candy = 54 pieces.
You want a box with only 9 pieces.
Each box has 18 pieces now.
So, just move 9 from one box to another.
1. At a basketball game, the ratio of the number of freshmen who attended to the number of juniors who attended was 3 to 4. The ratio of the number of juniors who attended to the number of seniors who attended was 7 to 6. What was the ratio of the number of freshmen to the number of seniors who attended?
-So its like 3:4 and 7:6 and do you add then or something? I am so confused, apparently the answer is 7 to 8?
2. Each of 3 boxes contains 18 pieces of candy. What is the least number of pieces of candy that can be moved from one box to another so that the box with the least number of pieces of candy contains 1/6 of the total number of pieces of candy?
-3:18-->1:6? Then 1:3? The answer key says 9... 6+3? I am pretty sure I am wrong haha
1 answer
1 answer